bisegment

— If the Arches BI and IK be cut in the middle in a, and b, likewiſe the Arches DM, ML being cut in the middle in c and d; and the Chords of the Bifegments in the Arch BK being drawn; likewiſe the Chords of the Biſegments in the Arch DL; alſo theſe will be as AB to AD, and they will always be ſo, if the Biſegments of the Bifegments proceed infinitely. Alſo the fame is true in the Biſections of the Arches KC and LE. But the Chords of the Biſegments infinite in number are equal to the Arch itſelf. For if all the Chords were leſs than all their Arches, there might yet a Biſection proceed; which is contrary to the ſuppoſition.